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CWNP Wireless Network Administrator (CWNA) Sample Questions (Q50-Q55):

NEW QUESTION # 50
In an 802.11 2.4 GHz system, what 22 MHz channels are considered non-overlapping?

• A. 1 and 5
• B. 7 and 11
• C. 4 and 6
• D. 2 and 8

Answer: A

Explanation:
In the 2.4 GHz frequency band used for 802.11 wireless networks, the channel bandwidth is typically 20 MHz, but the actual frequency spread of each channel is about 22 MHz due to the modulation techniques used. This spread causes overlap between adjacent channels, which can lead to interference and degrade network performance. To avoid this, it's essential to use non-overlapping channels.
The three non-overlapping channels in the 2.4 GHz band are 1, 6, and 11. Each of these channels is spaced sufficiently apart to avoid interference with each other:
* Channel 1: Centered at 2.412 GHz.
* Channel 6: Centered at 2.437 GHz.
* Channel 11: Centered at 2.462 GHz.
Given the options provided, option C (1 and 5) is the closest to a pair of non-overlapping channels, although in practice, channel 5 would still cause some interference with channel 1 due to the 22 MHz spread. The ideal choice for non-overlapping channels would be any two channels among 1, 6, and 11, but this is not an option provided. Therefore, within the given options, 1 and 5 are the best choice, understanding that in a real-world scenario, 1 and 6 or 6 and 11 would be preferred to avoid overlap.
References:
* CWNA Certified Wireless Network Administrator Official Study Guide: ExamCWNA-109, by David D: Coleman and David A. Westcott.
* Understanding 2.4 GHz channel arrangement and interference patterns in 802.11 wireless networks.

NEW QUESTION # 51
You are configuring an access point to use channel 128. What important fact should be considered about this channel?

• A. It is a 2.4 GHz frequency band 40 MHz channel, so it should not be used
• B. It is a channel that is unsupported by all access points in all regulatory domains
• C. It is a 22 MHz channel so it will overlap with the channels above and below it
• D. It is a channel that may require DFS when used

Answer: D

Explanation:
It is a channel that may require DFS when used is an important fact that should be considered about channel
128. Channel 128 is a 5 GHz frequency band 20 MHz channel that has a center frequency of 5.64 GHz.
Channel 128 is one of the channels that are subject to DFS (Dynamic Frequency Selection) rules, which require Wi-Fi devices to monitor and avoid using channels that are occupied by radar systems or other primary users. DFS is a feature that is defined in the IEEE 802.11h amendment and is mandated by some regulatory bodies, such as the FCC and the ETSI, to protect the licensed users of the 5 GHz band from interference by unlicensed Wi-Fi devices. DFS works by using a mechanism called channel availability check (CAC), which requires Wi-Fi devices to scan a channel for a certain period of time before using it. If a radar signal is detected during the CAC or while using the channel, the Wi-Fi devices must switch to another channel that is free from radar interference.
When configuring an access point to use channel 128, it is important to consider the implications of DFS rules, such as:
* The access point must support DFS and comply with the local regulations and standards that apply to DFS channels.
* The access point may experience delays or interruptions in its operation due to CAC or channel switching.
* The access point may have limited channel selection or availability due to radar interference or other Wi-Fi devices using DFS channels.
* The access point may have compatibility or interoperability issues with some client devices that do not support DFS or use different DFS parameters.
* The access point may have performance or quality issues due to co-channel or adjacent-channel interference from other Wi-Fi devices using non-DFS channels.
Therefore, it is advisable to use channel 128 only when necessary and after performing a thorough site survey and spectrum analysis to determine the best channel for the access point. References: 1, Chapter 3, page
117; 2, Section 3.2

NEW QUESTION # 52
An 802.11 WLAN transmitter that emits a 50 mW signal is connected to a cable with 3 dB of loss. The cable is connected to an antenna with 16 dBi of gain. What is the power level at the Intentional Radiator?

• A. 250 mW
• B. 500 mW
• C. 1000 mW
• D. 25 mW

Answer: A

Explanation:
The power level at the Intentional Radiator (IR) is 250 mW. The IR is the point where the RF signal leaves the transmitter and enters the antenna system. To calculate the power level at the IR, we need to consider the output power level of the transmitter, the loss of the cable, and the gain of the antenna. The formula is:
Power level at IR (dBm) = Output power level (dBm) - Cable loss (dB) + Antenna gain (dBi) We can convert the output power level of 50 mW to dBm by using the formula:
Power level (dBm) = 10 * log10(Power level (mW))
Therefore, 50 mW = 10 * log10(50) = 16.99 dBm
We can plug in the values into the formula:
Power level at IR (dBm) = 16.99 - 3 + 16 = 29.99 dBm
We can convert the power level at IR from dBm to mW by using the inverse formula:
Power level (mW) = 10

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